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3x^2+37x-104=0
a = 3; b = 37; c = -104;
Δ = b2-4ac
Δ = 372-4·3·(-104)
Δ = 2617
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{2617}}{2*3}=\frac{-37-\sqrt{2617}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{2617}}{2*3}=\frac{-37+\sqrt{2617}}{6} $
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